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Theoretical Physics Practical Training
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      1 # Classical Teleportation
      2 
      3 We are asked to discuss sending matter (A) or information (B) with respect to
      4 the following questions
      5 
      6     * a) scenario (A), decomposing a human being or a piece of matter before
      7       sending, where would you stop decomposing (organ level, cell level,
      8       molecule level, atom level or smaller)? Choose a level and think what
      9       technical limits a decomposition and rebuilding would require roughly
     10 
     11       Answer:
     12         All in all the smaller we go the harder it is to
     13         decompose, but the faster it is to send. To understand what I mean
     14         consider we decompose on the organ level, then we have massive parts
     15         that need to be sent from point A to point B via normal transportation,
     16         i.e. bus, car or even a spaceship. The transportation method itself
     17         would make the term 'teleportation' meaningless. On the other hand say
     18         we decompose on the molecule level however impossible it may be. Now the human
     19         body is made of roughly 80% H20 imagine we have constructed a safe vacuum
     20         pipeline to send H20 particles from point A to B, with a roughly
     21         estimated velocity  of 0.01% of the speed of light, this would make the atom
     22         level teleportation faster in terms of transportation than organ level
     23         teleportation. But the issues we would face of decomposing a human body into
     24         atoms and then putting it back together are immense, not to even
     25         mention if we can be absolutely be certain we can compose the same
     26         person again, without losing personality/memory.
     27 
     28     * b) consider (A) and assume you want to send atoms. How long would it take
     29       to transfer the atoms of a typical human being?
     30 
     31       Answer:
     32         There are approximately 7*10^27 atoms in a 70kg adult body, where 80% are
     33         hydrogen (54%) and oxygen (26%). The ionization energy of hydrogen is
     34         13.6 eV meaning the maximum speed hydrogen can travel before becoming purely an
     35         electron and a proton is roughly 0.01% the speed of light and for
     36         oxygen we have 0.0025% so in the mean lets
     37         say 0.0025% the speed of light (compensating the other 20% more massive
     38         than hydrogen that we didn't consider).
     39         That means to send an atom of the human body from earth to the sun
     40         (150*10^9 m) we would need about 74 days. Now for the mean atom radius
     41         of the atoms in the human body we take oxygen (60pm), forming a straight
     42         line of 7*10^27 atoms of 60pm radius we have 8.4*10^17 m. The conclusion
     43         is it would take too long to send them.
     44 
     45     * c) consider (B) say each lattice pos. (10^-10m) of the volume of the
     46       human being is filled with an atom (hydrogen, oxygen, calcium, kalium) or
     47       no atom. How many bits do you need to describe one lattice position, how
     48       much of the human being (2x1x1m)? Assume each bit is encoded by a light
     49       pulse of a frequency of 2*10^-15s? How long would it roughly take to send
     50       the full information of the position of the atoms of a human being?
     51 
     52       Answer:
     53         Since a bit can be either a "1" or a "0" and we need to encode 6
     54         possible outcomes that can be in one lattice, hydrogen, oxygen,
     55         calcium, kalium or no atom. This can be done with 3 bits. As for the
     56         human body we need to map a discrete 3-d space of resolution 10^-10
     57         from 2x1x1m and the 6 possible outcomes indicating which atom is or is
     58         not in a lattice. The resolution of 10^-10 for three numbers plus 6
     59         outcome posibilities can be encoded in
     60         log_2(10^10) \simeq [35](35) bits (round up!)